Решите пж (5x-7)(8x+1)=(8x+1)^2

$(5x-7)(8x+1)=(8x+1)^{2} \\ 40x^{2}+5x-56x-7=64x^{2}+16x+1 \\ 40 x^{2} -51x-7-64 x^{2} -16x-1=0 \\ -24 x^{2} -67x-8=0 \\ D=(-67)^{2} -4*(-24)*(-8)=4489-768=3721. \\ x(1)= \frac{-(-67)- \sqrt{3721} }{2*(-24)} = \frac{67-61}{-48}= \frac{6}{-48} =-0.125 \\ x(2)= \frac{-(-67)+ \sqrt{3721} }{2*(-24)} = \frac{67+61}{-48}= \frac{128}{-48} = -\frac{8}{3} \\$
Ответ: -0.125; -8/3.