Решите пж срочно надо

Question

Решите пж срочно надо

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Answer 1

Ddffddfddddffffffddfffff

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Answer 2

1)3/(2x-y)-2/(2x+y)=(6x+3y-4x+2y)/(4x²-y²)=(2x+5y)/(4x²-y²)
2)(2x+5y)/(4x²-y²)-1/(2x-5y)=(4x²-25y²-4x²+y²)/(4x²-y²)(2x-5y)=
=-24y²/(4x²-y²)(2x-5y)
3)-24y²/(4x²-y²)(2x-5y):y²/(4x²-y²)=-24y²/(4x²-y²)(2x-5y)*(4x²-y²)/y²=
=-24/(2x-5y)=24/(5y-2x)