Решите пж срочно надо

Question

Решите пж срочно надо

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Answer 1

1)(y-x)²/x²-(x²+2xy+y²-4xy)/x(x-y)=(y-x)²/x²-(x²-2xy+y²)/x(x-y)=
=(y-x)²/x²-(x-y)²/x(x-y)=(y-x)²/x²-(x-y)/x=(y²-2xy+x²-x²+xy)/x²=
=(y²-xy)/x²=y(y-x)/x²
2)[y(y-x)/x²]²=y²(y-x)²/x^4
3)y²(y-x)²/x^4 *x^4/y²(x²-y²)=(x-y)²/(x-y)(x+y)=(x-y)/(x+y)

Answer 2

См.прикрепленный файл!

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