√2 sin (п/4 - х/2)=>1 решить неравенство
Sin(π/4 - x/2) ≥ 1/√2 sin(x/2 - π/4) ≤ - 1/√2 - 3π/4 + 2πn ≤ x/2 - π/4 ≤ - π/4 + 2πn - π/2+ 2πn ≤ x/2 ≤ 2πn - π+ 4πn ≤ x ≤ 4πn