Решите уравнение 6sin^2 x-cosx-5=0
6(1 - Cos²x) - Cosx - 5 = 0 6 - 6Cos²x - Cosx -5 = 0 6Cos²x + Cosx -1 = 0 D = 25 Cosx = (-1+5)/12= 1/3 б) Cosx = (-1 -5)/12 = -1/2 x = +-arcCos1/3 + 2πk, k ∈Z x = +-2π/3+ 2πn, n ∈Z