1+2log(x+5) 5=log5(x+5)
ОДЗ x>-5
x≠-4
loga b = 1/logb a
1+2log(x+5) 5=1/log(x+5) 5
log(x+5) 5+2log²(x+5) 5=1
log(x+5) 5 = t
2t²+t-1=0
D=1+8=9
t12=(-1+-3)/4= -1 1/2
t=-1
log(x+5) 5 = -1
1/(x+5)=5
5x+25=1
x=-24/5=-4.8
t=1/2
√(x+5)=5
x+5=25
x=20
ответ -4.8 20