1)5y+y²-(y+3)²= 2)(x+3)(x-3)-x²+2x=0

Question

1)5y+y²-(y+3)²=
2)(x+3)(x-3)-x²+2x=0

Answer 1

1) 5у+у²-(у²+6у+9)=5у+у²-у²-6у-9=-у-9
2)х²-9-х²+2х=
-9+2х=0
2х=9
х=4,5