Решите уравнение! 2 соs^2x+cos2x=0
Cos2x(2cosx+1) cos2x=0 x= Pi/2+Pin,n z 2cosx+1=0 2cosx=-1 cosx=-1/2 x=+- arccos(-1/2)+2pin n z x=+- (Pi-arccos(1/2)) + 2Pin n z x=+- (Pi-Pi/3)+2pin n z x=+-(3Pi/3-Pi/3)+2Pin n z x=+- 2Pi/3+2Pin n z