1) (x-2) во 2 + (x-1)(x+3)=? 2) (y+3) во 2 - (2y-5)(y-6)=? помогите плиииз даю 20 б

Question

1) (x-2) во 2 + (x-1)(x+3)=?
2) (y+3) во 2 - (2y-5)(y-6)=?
помогите плиииз даю 20 б

Answer 1

(2-x)²+(x-1)(x+3)=4-4x+x²+x²+3x-x-3=0   2x²-2x+1=0 D=4-4×2=0 x=2÷4=0.5
(y+3)²-(2y-5)(y-6)=y²+6y+9-2y²+12y+5y-30=-y²+23y-30=y²-23y+30=0
тут хз

Comments

спс!