Решите: 1) 16^x-9=1/2 2) (5x-3)^2=(5x+13)^2 3) x-6/7x+3=x-6/5x-1

$1) 16^{x-9}= \frac{1}{2} \\ \\ (2^4)^{x-9}=2^{-1} \\ \\ 2^{4x-36}=2^{-1} \\ \\ 4x-36=-1 \\ \\ 4x=-1+36 \\ \\x=35 \\ \\ x= \frac{35}{4} \\ \\ x=8 \frac{3}{4} \\$

$2) (5x-3)^2=(5x+13)^2 \\ \\ 25 x^{2} -30x+9=25 x^{2} +130x+169 \\ \\ 130x+30x=-169+9 \\ \\ 160x=-160 \\ \\ x=-1$

3) ОДЗ
7х+3≠0
х≠-3/7
5х-1≠0
5х≠1
х≠0,2

$\frac{x-6}{7x+3} = \frac{x-6}{5x-1} \\ \\ x-6=0 \\ \\ x_1=6 \\ \\ \frac{1}{7x+3}= \frac{1}{5x-1} \\ \\ 5x-1=7x+3 \\ \\ 7x-5x=-1-3 \\ \\ 2x=-4 \\ \\ x_2=-2$