Помогите найти интегралы
1а) ∫(2 - 3x^5 +4x + 3x^2) dx = 2x - (1/2) x^6 + 2x^2 + x^3 + C 1б) ∫ ( (1-3x)^(1/3) ) dx Замена u = 1 -3x; du = -3x dx; dx = - du/3 ∫ ((1-3x)^(1/3)) dx = (-1/3) ∫u^(1/3) du = (-1/3) * (3/4) * u^(4/3) = -(1/4)*(1-3x)^(4/3) + C