A) (125/0.2)^(1/4) = (125 / (1/5))^(1/4) = (5^3 * 5)^(1/4) = (5^4)^(1/4) = 5
б) (16/0.0625)^(1/4) = (16 / (1/16))^(1/4) = (16*16)^(1/4) = (2^4 * 2^4)^(1/4) = (2^4)^(1/4) * (2^4)^(1/4) = 2 * 2 = 4
в) (27/0,125)^(1/3) = ( (3^3) / (0.5^3) )^(1/3) = 3 / 0.5 = 6
г) (16/0.25)^(1/6) = ( 16 / (1/4) )^(1/6) = (64)^(1/6) = ( 2^6 )^(1/6) = 2