Дано
m(Na2CO3)=42,4 g
CH3COOH
-------------------------
V(CO2)-?
m(CH3COOH)-?
42.4 Y X
Na2CO3+2CH3COOH-->2CH3COONa+H2O+CO2
106 2*60 22.4
M(Na2CO3)=106 g/mol , Vm=22.4 L/mol M(CH3COOH)=60 g/mol
X=42.4*22.4 / 106
X=8.96 L -CO2
y=42.4*120 / 106
y=48 g - CH3COOH
ответ 8.96 л , 48 г