Помогите решить sin x - √3cos x = 2
Разделим на 2 обе части. 1/2 sinx - √3/2 cosx = 1 sinx · cos(π/3) - sin(π/3) · cosx = 1 sin(x - π/3) = 1 x - π/3 = π/2 + 2πn x = 5π/6 + 2πn