Решите срочно пожвлуйстаааа
3Sin2x -13SinxCosx + 4Cos2x = 0 3Sinx - 6,5*2SinxCosx + 4Co2x = 0 3Sin2x - 6,5Sin2x + 4Cos2x = 0 -3,5Sin2x - 4Cos2x = 0 | : Cos2x ≠ 0 -3,5tg2x -4 = 0 -3,5tg2x = 4 tg2x = -4/3,5= -8/7 2х = -arctg(8/7) + πk , k ∈ Z x = -0,5arctg(8/7) + πk/2 , k ∈ Z