Помогите!!! решить неравенства
4^x - 2^(x + 1) - 8 < 0 4^x - 2^x*2 - 8 < 0 2^x = t t^2 - 2t - 8 < 0 t^2 - 2t - 8 = 0 D = 4 + 32 = 36 t1 = (2 + 6)/2 = 8/2 = 4 t2 = (2 - 6)/2 = - 4/2 = - 2 2^x = 4 x = 2 x - 2 < 0 x < 2 x ∈ ( - ∞; 2)