Решите уравнение .

$sin[tex]Sin(5x) = -1$ 5x = -1[/tex]
Sin (π - 5х) = -1
5х = arcsin (-1)
π - 5x = arcsin (-1)
5x = - π/2
π - 5x = - π/2
5x = - π/2 + 2kπ
π - 5x = - π/2 +2 kπ
x = -π/10 + 2kπ/5
x = 3π/1- - 2kπ/5
x = -π/10 + 2kπ/5
x = 3π/10 + 2kπ/5
-----
| - π/10 + 2kπ/5
x =
| 3π/10 + 2kπ/5
-----
____________________________________________________________
π - число пи

-----
| - π/10 + 2kπ/5
x = = $\left \{ {{y=2} \atop {x=2}} \right.$
| 3π/10 + 2kπ/5
-----
(Что бы было понятно)