Решить уравнение -cos2x - 1=3 cos (7пи/2-x)
Cos(7П/2-x)=cos(3П/2-x)=-sinx -cos2x-1=-3sinx cos2x+1=3sinx 1-2sin^2x+1=3sinx 2sin^2x+3sinx-2=0 sinx=t -1<=t<=1<br>2t^2+3t-2=0 t=-3+-√(9+16)/4=(-3+-5)/4 t=1/2 sinx=1/2 x=(-1)^kП/6+Пk