Найдите корень уравнения 4y(y-3)-(2y-1)^2=0

Question

Найдите корень уравнения 4y(y-3)-(2y-1)^2=0

Answer 1

4y^2 - 12y - (4y^2 - 4y + 1) = 0
4y^2 - 12y - 4y^2 + 4y - 1 = 0 
- 8y - 1 = 0
- 8y = 1
8y = - 1
y = - 1/8 = - 0,125