Письменно пожалуйста
1) 2х + π/6 = 2πk , k ∈Z 2x = 2πk - π/6, k ∈Z x = πk - π/12, k ∈ Z 2) 4x = π/2 + πk , k ∈Z x = π/8 + πk/4 , k ∈Z 3) x = +-arcCos(π/2) + 2πk , k ∈Z 4) 2x = +-arcCosπ + 2πk , k ∈Z x = +-1/2*arcCosπ + πk , k ∈Z 5)x = +-arcCos(4/7)+ 2πk , k ∈Z