Х+2(у+6)=3х-у РЕШИТЕ СИСТЕМУ УРАВНЕНИЙ 5х-у+3=4(х-у)

Решите задачу:

$\left \{ {{x+2(y+6)}=3x-y \atop {5x-y+3=4(x-y)}} \right. \\ \left \{ {{x+2y+12}=3x-y \atop {5x-y+3=4x-4y}} \right. \\ \left \{ {{3y= 2x-12} \atop {x+3=-3y}} \right. \\ \left \{ {{3y-2x=-12} \atop {x=-3-3y}} \right. \\ \left \{ {{3y+ 2(3+3y)=-12} \atop {x=-3-3y}} \right. \\ \left \{ {{9y=-18} \atop {x=-3-3y}} \right. \\ \left \{ {{y=-2 \atop {x=-3+6 }} \right. \\ \left \{ {{y=-2 } \atop {x= 3}} \right.$