2 х/5 + 1 = у/2 2х/5 + у = -2 3 х+2 у=10 5 х+3 у=12

$\left \{ { \frac{2x}{5}+1 = \frac{y}{2} } \atop { \frac{2x}{5}+y=-2 }} \right. \\\\ 1-y= \frac{y}{2}+2\ \ |\cdot(-2)\\\\ 2y+y=-2\\\\ 3y=-2\\\\ y=- \frac{2}{3}\\\\\\ \frac{2x}{5}- \frac{2}{3}=-2\\\\ \frac{2x}{5}=-2+ \frac{2}{3} \ \ | \cdot15 \\\\ 6x=-30+10\\\\ 6x=-20\\\\ x=- \frac{10}{3}$

Ответ: $(- \frac{10}{3}; - \frac{2}{3})$

$\left \{ {{3x+2y=10 \ \ |\cdot3} \atop {5x+3y=12} \ \ |\cdot2} \right. \\\\\\ \left \{ {9x+6y=30} \atop {10x+6y=24}} \right.\\\\ -x=6\\ x=-6\\\\ 3\cdot(-6)+2y=10\\ -18+2y=10\\ 2y=28\\ y=14$

Ответ: $(-6;14)$