is second question correct?
второе задание без ошибок?
без
you chanced your question?
1. ОДЗ 7-x>0 -х>-7 При x<7<br>Ответ: при х∈ ]∞; 7[ 2. ОДЗ х² - 8х + 15 > 0 х² - 8х + 15 = 0 D = b² -4ac D = 64 - 4 · 1 · 15 = 64 - 60 = 4 √D = √4 = 2 x₁ = (8 + 2)/2 = 10/2 = 5 x₂ = (8-2)/2 = 6/2 =3 (x-5)(x-3) > 0 ___+____3___-______5____+_____ При x <3; x> 5 Ответ: при х ∈ ]-∞; 3[∪]5; +∞[
1) 7 - x > 0 x < 7 2) x² - 8x + 15 >0 (x - 3)(x - 5) > 0 x∈( - ∞; 3) ∪ (5 ; + ∞)