Log (2) (x) + (log (2) (x)) / (log (2) (3)) = 1
(log (2) (3)) * log (2) (x) + log (2) (x) = log (2) (3)
(log (2) (3) + 1) * log (2) (x) = log (2) (3)
log (2) (6) * log (2) (x) = log (2) (3),
log (2) (x) = (log (2) (3)) / (log (2) (6))
по определению логарифма:
2 ^ ( (log (2) (3)) / (log (2) (6)) ) = x
x = ( 2 ^ (log (2) (3)) ) ^ ( 1/ (log (2) (6)) )
x = 3 ^ ( log (6) (2) ) (интересно, что это же = 2 ^ ( log (6) (3) )
кажется нигде не ошиблась...