Помогите с системой 2х+у=-1 внизу х^2+2у=3

Question

Помогите с системой 2х+у=-1 внизу х^2+2у=3

Answer 1

2x + y = - 1
x^2 + 2y = 3

y = - 2x - 1
x^2 + 2( - 2x - 1) = 3*

x^2 - 4x - 5  = 0 
D = 16 + 20 = 36
x1  = (4 +  6)/2 = 10/2 = 5
x2  = (4 -  6)/2 = - 2/2 = - 1

x1 = 5
y1 = - 2x1 - 1 = - 10 -  1= - 11

x2 = - 1
y2 = - 2x2 - 1 = 2 - 1 = 1