Решите уравнения: (1+2cosx)(1-3cosx)=0
(1+2cosx)(1-3cosx)=0 1+2cosx=0 или 1-3cosx=0 1. 1+2cosx=0 2cosx=-1 cosx=-1/2 x=+-(π-π/3)+2πn, n∈Z x=+-(2π/3)+2πn, n∈Z 2. 1-3cosx=0 3cosx=1 cosx=1/3 x=+-arccos1/3+2πn, n∈Z