() -основание логарифма
log(√3) 1/3 – log(0.2) 5 + log(64) 4 = (1)
log(√3) 1/3 =log(√3) 1/√3² =log(√3) √3^(-2) = -2 log(√3) √3 = -2 *1 = -2
log(0.2) 5 = log(1/5) (1/5)^-1 = -1*log(1/5) (1/5) = -1*1 = -1
log(64) 4 =log(64) ³√(4)³ =log(64) ³√64 = log(64) 64^(1/3)= 1/3 log(64) 64=1/3 *1= 1/3
подставляем значения в (1) = -2 -(-1) +1/3 = -2+1 +1/3 = -2/3
ОТВЕТ - 2.3