4x в квадрате +7x+3/x+1

Question

4x в квадрате +7x+3/x+1

Answer 1

(4x^2+7x+3)/(x+1)=

=(4x^2+4x+3x+3)/(x+1)=

=(4x*(x+1)+3(x+1))/(x+1)=

=((4x+3)*(x+1))/(x+1)=

=4x+3

Answer 2

4x2+7x+3/x+1=0 умножаем все на x
4x3+7x2+x+3=0
x2(4x+7)+(x+3)=0
x1=0
x2=-3
x3=-1,75