1522.
2х+1 х–2у 4(2х+у)
1) {------- – -------- = ----------
3 5 15
х–4у 5х–11у 3х–1
{-------- + --------- = -------
3 6 4
10х+5–3х+6у 8х+4у
{-------------------- = ---------
15 15
4х–16у+10х–22у 3х–1
{------------------------- = -------
12 4
7х+6у+5 8х+4у
{------------- = ---------
15 15
14х–38у 3х–1
{------------- = -------
12 4
{7х+6у+5=8х+4у
–х+2у+5=0
х=2у+5
14(2у+5)–38у 3(2у+5)–1
{-------------------- = --------------
12 4
28у+70–38у 6у+15–1
------------------ = ------------
12 4
70–10у 6у+14
----------- = ---------
12 4
70–10у 6y+14
----------- – -------- = 0
12 4
70–10y–18y–42
----------------------- = 0
12
28–28y=0
28y=28
y=1
x=2•1+5=7
Ответ: (7;1)
7х+у 5х–у х+у
2) {-------- – --------- = ------
3 2 6
9х–2у 7х+4у х+у
{---------- + --------- = ------ + 4
8 6 3
14х+2у–15х+3у х+у
{----------------------- = -----
6 6
27х–6у+28х+16у х+у+12
{------------------------- = ----------
24 3
–х+5у=х+у
2х=4у
х=2у
54у–6у+56у+16у 2у+у+12
{-------------------------- = -----------
24 3
120у 3(у+4)
{-------- = ----------
24 3
120у
{-------- = у+4
24
120у=24у+96
96у=96
у=1
х=2•1=2
Ответ: (2;1)