Примеры с решением!!!

Question 1

Question 2

Пожалуйста!!!

Question 3

Срочно

Question 4

Г)
$\frac{5}{24} - \frac{1}{60} - \frac{1}{40} = \frac{5*10 - 1*4 -1*6}{240}= \frac{50-10}{240}= \frac{40}{240} = \frac{40:40}{240:40} = \frac{1}{6}$

д)
$\frac{5}{14} + \frac{10}{21} -\frac{3}{4} = \frac{5*6}{14*6} + \frac{10*4}{21*4} - \frac{3*21}{4*21} = \\ \\ = \frac{30+40-63}{84} = \frac{70-63}{84} = \frac{7}{84} = \\ \\ = \frac{7:7}{84:7} = \frac{1}{12}$

е)
$\frac{5}{6} - \frac{3}{16} + \frac{5}{12} = \frac{5*8}{6*8} - \frac{3*3}{16*3} + \frac{5*4}{12*4} = \\ \\ = \frac{40 - 9 + 20 }{48} = \frac{51}{48}= \frac{51:3}{48:3}= \frac{17}{16}=1 \frac{1}{16}$

ж)
$(\frac{7}{10} + \frac{3}{5} ) - ( \frac{1}{6} +\frac{2}{3} ) = \\ \\ = (\frac{7}{10} + \frac{3*2}{5*2}) - ( \frac{1}{6} + \frac{2*2}{3*2} )= \\ \\ = \frac{7+6}{10} - \frac{1+4}{6} = \frac{13}{10} - \frac{5}{6} = \\ \\ = \frac{13*3}{10*3} - \frac{5*5}{6*5} = \frac{39-25}{30} = \\ \\ = \frac{14}{30} = \frac{14 :2}{30:2} = \\ \\ = \frac{7}{15}$

з)
$\frac{2}{3} - ( \frac{1}{20} + \frac{2}{9}) - \frac{5}{18}= \frac{2*60}{3*60} - ( \frac{1*9}{20*9} + \frac{2*20}{9*20}) - \frac{5*10}{18*10}= \\ \\ = \frac{120}{180} - \frac{9+40}{180} - \frac{50}{180} = \frac{120-49-50}{180} = \frac{21}{180} = \frac{21:3}{180:3} = \frac{7}{60}$

и)
$\frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} + \frac{1}{7} = \frac{1*140+1*105+1*84+1*70+1*60}{420} = \\ \\ = \frac{459}{420} = = \frac{459:3}{420:3} = \frac{153}{140} = 1 \frac{13}{140} \\$

№2.
в)
$(\frac{29}{44} + \frac{1}{6} ) - \frac{7}{44} = \frac{29}{44} + \frac{1}{6} - \frac{7}{44} = \frac{29-7}{44} + \frac{1}{6} = \\ \\ = \frac{22}{44} + \frac{1}{6} = \frac{1}{2} + \frac{1}{6} = \frac{1*3+1}{6} = \frac{4}{6} = \frac{2}{3}$

г)
$( \frac{5}{18} + \frac{19}{36} ) - \frac{1}{36} = \frac{5}{18} + \frac{19}{36} - \frac{1}{36}= \frac{5}{18} + \frac{19-1}{36} = \\ \\= \frac{5}{18} + \frac{18:2}{36:2} = \frac{5+9}{18} = \frac{14}{18} = \frac{7}{9}$

д)
$\frac{35}{68}- ( \frac{1}{68} + \frac{7}{22} ) = \frac{35}{68}- \frac{1}{68}- \frac{7}{22} = \\ \\ = \frac{34}{68}- \frac{7}{22} = \frac{1}{2} - \frac{7}{22} = \frac{1*11-7}{22}= \\ \\ = \frac{4}{22} = \frac{2}{11}$

е)
$\frac{14}{39} - ( \frac{1}{12} + \frac{1}{39} )= \frac{14}{39}- \frac{1}{12} - \frac{1}{39} = \frac{14-1}{39} - \frac{1}{12} = \frac{13}{39}- \frac{1}{12} = \\ \\ = \frac{1}{3}- \frac{1}{12} = \frac{4}{12} -\frac{1}{12} = \frac{3}{12} = \frac{1}{4}$