(11-2x²)/(x²-1)≥1
ОДЗ: x²-1≠0 (x-1)(x+1)≠0 x≠1 x≠-1
(11-2x²)/((x-1)(x+1))-1≥0
((11-2x²)-(x²-1))/((x+1)(x-1))≥0
(11-2x²-x²+1)/((x-1)(x+1))≥0
(-3x²+12)/((x-1)(x+1))≥0
-3*(x²-4)/((x-1)(x+1))≥0 |÷(-3)
(x-2)(x+2)/((x-1)(x+1))≤0
-∞____+____-2_____-____-1____+____1_____-_____2____+____+∞
x∈[-2;-1)U(1;2].
Ответ: x₁=-2 x₂=2.