24sin14^ cos14^ cos28^ ----------------------------------- cos34^

Решите задачу:

$\frac{24sin14 ^{0}*cos 14^{0}*cos 28^{0} }{cos 34^{0} }= \frac{12*(2sin 14^{0}*cos 14^{0} )*cos28 ^{0} }{cos 34^{0} } = \frac{12*sin28 ^{0}*cos28 ^{0} }{cos 34^{0} } =$
$= \frac{6*(2sin28 ^{0} *cos 28^{0} )}{cos34 ^{0} } = \frac{6*sin 56^{0} }{cos 34^{0} }= \frac{6*sin( 90^{0}-34^{0} )}{cos 34^{0} } = \frac{6*cos 34^{0} }{cos34^{0} } =6$