Помогите решить уравнения!!!!!!!!! 1) 3^(-x ) + 3^(x+3) =12 2) lg(100x)*lg(0,001) + 4 =0
3ˣ=z 1/z+27z-12=0 27z²-12z+1=0 D=144-4*27=36 √36=6 z1=1/54[12+6]=1/3 3ˣ=3⁻¹ x=-1 z2=1/54[12-6]=1/9 3ˣ=3⁻² x=-2 ------------------------------------------------ lg100x*lg0.001+4=0 (lg100+lgx)(-3)=12 2+lgx=-4 lgx=-6 x=10⁻⁶