Sin2x+sin6x=3cos2x..

Question

Sin2x+sin6x=3cos2x..

Answer 1

Sin(2x)+sin(6x)=3cos(2x)
2sin(4x)*cos(-2x)-3cos(2x)=0
2sin(4x)*cos(2x)-3cos(2x)=0
cos(2x)*(2sinx-3)=0
a) cos(2x)=0
2x=π/2+πn
x1=π/4+πn/2
б) 2sinx-3=0