F(x)=x^4-10x^2+9
f'(x)=4x^3-20x
4x^3-20x=0
4x(x^2-5)=0
x1=0, x2=sqrt(5), x3= -sqrt(5)
-------------______+++++++_____-------------_____+++++++ f'(x)
↓ -sqrt(5) ↑ 0 ↓ sqrt(5) ↑ f(x)
min max min
f(-sqrt(5))= (-sqrt(5))^4-10(-sqrt(5))^2+9= -16
f(0)=9
f(sqrt(5))= sqrt(5)^4-10*sqrt(5)^2+9= -16
Ответ: fmax=9, fmin= -16