3)\\ OTBET: x=1" alt="4^{\sqrt{x}}-0,5^{x-3}=0\\ ODZ: x\geq 0\\ 2^{2\sqrt{x}}-2^{3-x}=0\\ 2^{2\sqrt{x}}=2^{3-x}\\ 2\sqrt{x}=3-x\\ \begin{cases}4x=9-6x+x^2\\ 3-x\geq 0\end{cases}\\ \begin{cases}x^2-10x+9=0\\ x\leq 3\end{cases}\\ x_1=1, x_2=9(x> 3)\\ OTBET: x=1" align="absmiddle" class="latex-formula">