Решите уравнение tg^2 x=tgx

Решите задачу:

$tg^2 x=tgx \\ \\ tg^2 x-tgx=0 \\ \\ tgx(tgx-1)=0 \\ \\ \left [ {{tgx=0;} \atop {tgx-1=0}} \right. \ \ \textless \ =\ \textgreater \ \ \left [ {{tgx=0;} \atop {tgx=1}} \right. \ \ \textless \ =\ \textgreater \ \ \left [ {{x= \pi n;} \atop {x= \frac{ \pi }{4}+ \pi n, \ n \in Z }} \right. \\ \\ OTBET: \ \pi n; \ \frac{ \pi }{4}+ \pi n, \ n \in Z$