Помогите решить.(я решила,но хочу проверить) x³+4x²=9x+36.
X^3 + 4x^2 - 9x - 36 = 0 x^2 (x + 4) - 9(x + 4) = 0 (x + 4)(x^2 - 9) = 0 (x + 4 ) (x - 3)(x + 3) = 0 x +4 = 0 x = - 4 x - 3 = 0 x = 3 x + 3 = 0 x = - 3
X^3 + 4x^2 = 9x + 36 x^2 ( x + 4 ) - 9( x + 4 ) = 0 ( x^2 - 9 )( x + 4 ) = 0 ( x - 3 )( x + 3 )( x + 4 ) = 0 x - 3 = 0 x = 3 x + 3 = 0 x = - 3 x + 4 = 0 x = - 4 Ответ 3 ; - 3 ; - 4