Решите уравнение :1 и 2

Первое уравнение:
$\frac{ \frac{2}{3} }{ \frac{4}{9} x- \frac{4}{9} } + \frac{1}{20}= \frac{4}{5}$
$\frac{ \frac{2}{3} }{ \frac{4}{9} x- \frac{4}{9} } = \frac{4}{5} - \frac{1}{20}$
$\frac{ \frac{2}{3} }{ \frac{4}{9} x- \frac{4}{9} } = \frac{15}{20}$
$\frac{ \frac{2}{3} }{ \frac{4}{9} x- \frac{4}{9} } = \frac{3}{4}$
${ \frac{4}{9} x- \frac{4}{9} } = \frac{2}{3} : \frac{3}{4}$
${ \frac{4}{9} x- \frac{4}{9} } = \frac{2}{3} * \frac{4}{3}$
${ \frac{4}{9} x- \frac{4}{9} } = \frac{8}{9}$
$\frac{4}{9} x= \frac{8}{9}+ \frac{4}{9}$
$\frac{4}{9} x= \frac{12}{9}$
$x=\frac{12}{9}:\frac{4}{9}$
$x=\frac{12}{9}:\frac{9}{4}$
$x=3$

второе:
$\frac{ \frac{5}{7} }{ \frac{6}{7} x+ \frac{3}{7} } - \frac{1}{2}= \frac{1}{6}$
$\frac{ \frac{5}{7} }{ \frac{6}{7} x+ \frac{3}{7} }= \frac{1}{6}+ \frac{1}{2}$
$\frac{ \frac{5}{7} }{ \frac{6}{7} x+ \frac{3}{7} }= \frac{4}{6}$
$\frac{ \frac{5}{7} }{ \frac{6}{7} x+ \frac{3}{7} }= \frac{2}{3}$
$\frac{6}{7} x+ \frac{3}{7}= \frac{5}{7} : \frac{2}{3}$
$\frac{6}{7} x+ \frac{3}{7}= \frac{5}{7} * \frac{3}{2}$
$\frac{6}{7} x+ \frac{3}{7}= \frac{15}{14}$
$\frac{6}{7} x=\frac{15}{14}-\frac{3}{7}$
$\frac{6}{7} x=\frac{15}{14}-\frac{6}{14}$
$\frac{6}{7} x=\frac{9}{14}$
$x=\frac{9}{14}:\frac{6}{7}$
$x=\frac{9}{14}*\frac{7}{6}$
$x= \frac{3}{4}$