Решите неравенство: 2cos(2x-3)=-2sin(2x-3)
=2cos(2x-3)\cos(2x-3) = -2sin(2x-3)\cos(2x-3) 2= - 2sin(2x-3)\cos(2x-3) 2=2tg(3-2x) 2tg(3-2x)=2 tg(3-2x)=1 3-2x= pi\4 +piK x= - pi+4piK-12\8