1)4m(2-n)-6+3n=? 2)x³-4x²-x+4=? .... (X+3)³-(x+3)²•x+3(x+3)=0

Question

1)4m(2-n)-6+3n=?
2)x³-4x²-x+4=?
....
(X+3)³-(x+3)²•x+3(x+3)=0

Answer 1

1) 4m(2-n)-6+3n=4m(2-n)-3(2-n)= (2-n)(4m-3)
2) x³-4x²-x+4 = x²(x-4)-(x-4) = (x-4)(x²-1)
3) (x+3)³-(x+3)²x+3(x+3) = (x+3)((x+3)²-x(x+3)+3) = (x+3)(x²+6x+9-x²-3x+3) = (x+3)(3x+12) = 3(x+3)(x+4)