{ x^2+y^2=0 (1)
{ y-x^2=-7 (2)
(2) {-x^2=-7-y
x^2=7+y
подставим (2) в (1)
x^2+y^2=0
7+y+y^2=0
y^2+y+7=0
д= 1+24=5^2
y= (-1+-5) \ 2 = -3; 2
подставим y в (1)
x^2=7+y
x^2=7-3 x^2=7+2
x^2=4 x^2=9
x=-+2 x=-+3
ответ y=-3; 2 x=-+2; -+3
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