Решите систему уравнений
(1/5)^(5x-y)=25 (1/5)^(5x-y)=(1/5)^(-2) 5x-y=-2 y=5x-2 2^(2x-y)=1/32 2^(2x-y)=2^(-5) 2x-y=-5 2x-(5x-2)=-5 2x-5x+2=-5 -3x=-7 x=2 и 1/3 y=5*(2 и 1/3)-2 =8 и 5/3=9 и 2/3