Решите уравнение (4х - 3 ) квадрат - ( 2х - 3 ) ( 2х +3 ) - ( 12х - 5 ) ( х + 1 ) = 116

Question

Решите уравнение (4х - 3 ) квадрат - ( 2х - 3 ) ( 2х +3 ) - ( 12х - 5 ) ( х + 1 ) = 116

Answer 1

(4x - 3)^2 - (4x^2 - 9) - (12x^2 + 12x - 5x - 5) = 116
16x^2 - 24x + 9 - 4x^2 + 9 - 12x^2 - 12x + 5x + 5 - 116 = 0 
12x^2 - 24x +18 - 12x^2 - 7x - 111 = 0
- 24x - 7x - 93 = 0 
- 31x - 93 = 0   
- 31x = 93
31x = - 93
x = - 3