Решите уравнение log 37 по основанию х, минус log x^2 по основанию 37 равно -1
Log37 x=z 1/z-2z+1=0 -2z²+z+1=0 2z²-z-1=0 z1=1 log37 x=1 x=37 z2=-0.5 log37 x=-0.5 x=1/√37
Logx(37) - 2log37(x) = -1 1/log37(x) - 2 log37(x) = -1 2log37(x)^2 - log37(x) - 1 = 0 t = log37(x) 2t^2 - t - 1 = 0 D = 1 + 8 = 9 t1 = (1+3)/4 = 1 t2 = (1-3)/4 = -1/2 log37(x) = 1 x = 37 log37(x) = -1/2 x = 1/корень(37)