Помогите пожалуйста, срочно

Question 1

Question 2

Решите задачу:

$|x-2| \leq 3\\ x-2 \geq 0, \ x \geq 2:\\ x-2 \leq 3\\ x \leq 5\\ x\in[2;3] \\ x-2\ \textless \ 0, \ x\ \textless \ 2:\\ 2-x \leq 3\\ 2-3 \leq x\\ x \geq -1\\ x\in[-1;2)\\ Otvet: \ x\in[-1;3]\\ \\ x^2-3|x|-4 \leq 0\\ x \geq 0:\\ x^2-3x-4 \leq 0\\ (x+1)(x-4) \leq 0\\ x\in[-1;4]\\ x\in[0;4]\\ x\ \textless \ 0:\\ x^2+3x-4 \leq 0\\ (x-1)(x+4) \leq 0\\ x\in[-4;1]\\ x\in[-4;0)\\ Otvet: \ x\in[-4;4]\\ \\ 5|2x+1| \geq -1\\ 2x+1 \geq 0, \ 2x \geq -1, \ x \geq -0,5\\ 5(2x+1) \geq -1\\ 10x+5 \geq -1\\ 10x \geq -6\\ x \geq -0,6\\ x\in [-0,5;+\infty)\\$
$2x+1\ \textless \ 0, \ 2x\ \textless \ -1, \ x\ \textless \ -0,5:\\ 5(-2x-1) \geq -1\\ -10x-5 \geq -1\\ -10x \geq 4\\ x \leq -0,4\\ x\in(-\infty;-0,5)\\ Otvet: \ x\in (-\infty;+\infty)\\ \\ |x|*|x-1| \geq 20\\ x \geq 0, \ x-1 \geq 0\\ x \geq 1:\\ x(x-1) \geq 20\\ x^2-x-20 \geq 0\\ D=81\\ x_1=5, \ x_2=-4\\ (x-5)(x+4) \geq 0\\ x\in(-\infty;-4]U[5;+\infty)\\ x\in [5;+\infty)\\ x \geq 0,\ x-1\ \textless \ 0\\ x \geq 0, \ x\ \textless \ 1\\ 0 \leq x\ \textless \ 1\\ x(1-x) \geq 20\\ x-x^2-20 \geq 0\\ x^2-x+20 \leq 0\\ D\ \textless \ 0\\ x\ \textless \ 0, \ x-1 \geq 0\\ x\ \textless \ 0, \ x \geq 0\\ net \ resheniy\\$
$x\ \textless \ 0, \ x-1\ \textless \ 0\\ x\ \textless \ 0, \ x\ \textless \ 1\\ x\in (-\infty;0)\\ -x(1-x) \geq 20\\ -x+x^2-20 \geq 0\\ x^2-x-20 \geq 0\\ D=81\\ x_1=4, \ x_2=-5\\ (x-4)(x+5) \geq 0\\ x\in (-\infty;-5]U[4;+\infty)\\ x\in (-\infty;-5]\\ Otvet: \ x\in(\infty;-5]U[5;+\infty)$