Помогите пожалуйста #1099

Решите задачу:

$1099\\1)\;\left(\frac57\right)^2\cdot\frac7{15}=\frac{25}{49}\cdot\frac7{15}=\frac57\cdot\frac13=\frac5{21}\\2)\;\left(\frac34\right)^2\cdot\frac{32}{45}=\frac9{16}\cdot\frac{32}{45}=\frac11\cdot\frac25=\frac25\\3)\;\left(\frac12\right)^2\cdot\frac45=\frac14\cdot\frac45=\frac15\\4)\;\left(2\frac57\right)^2\cdot\frac{14}{19}=\left(\frac{19}7\right)^2\cdot\frac{14}{19}=\frac{(19)^2}{7^2}\cdot\frac{14}{19}=\frac{19}7\cdot\frac21=\frac{38}7=5\frac37$
$5)\;\left(2\frac13\right)^2\cdot\frac{27}{98}=\left(\frac73\right)^2\cdot\frac{27}{98}=\frac{49}9\cdot\frac{27}{98}=\frac32=1\frac12\\6)\;\left(\frac8{11}\right)^2\cdot\frac{11}{32}=\frac{8^2}{(11)^2}\cdot\frac{11}{32}=\frac{64}{11}\cdot\frac1{32}=\frac2{11}\\7)\;\left(\frac3{10}\right)^2\cdot\frac56=\frac{3^2}{100}\cdot\frac56=\frac3{20}\cdot\frac12=\frac3{40}\\8)\;\left(\frac23\right)^2\cdot\frac{15}{24}=\frac49\cdot\frac{15}{24}=\frac13\cdot\frac56=\frac5{18}$