Решите 3 уровнения пожалуйста

1) $\frac{1}{x} + \frac{3}{2 \frac{2}{5}x }= \frac{3}{4}$
$\frac{2 \frac{2}{5}+3 }{2 \frac{2}{5}x} = \frac{3}{4}$
$4(2 \frac{2}{5}+3)=3(2 \frac{2}{5}x)$
$\frac{108}{5}= \frac{36}{5}x$
$x=3$

2) $\frac{1}{x} - \frac{2}{4 \frac{2}{3}x }= \frac{2}{7}$
$\frac{4 \frac{2}{3}-2 }{2 \frac{2}{3}x} = \frac{2}{7}$
$7(4 \frac{2}{3}-2)=2(4 \frac{2}{3}x)$
$\frac{56}{3}= \frac{28}{3}x$
$x=2$

3) $\frac{1}{x} + \frac{6}{3 \frac{1}{3}x }= \frac{2}{5}$
$\frac{3 \frac{1}{3}+6 }{3 \frac{1}{3}x} = \frac{2}{5}$
$5(3 \frac{1}{3}+6)=2(3 \frac{1}{3}x)$
$\frac{140}{3}= \frac{20}{3}x$
$x=7$