Решите уравнение 2cos²x-1=0
Cos^2x = 1/2 cosx = - √2/2 x₁ = ± arccos(-√2/2) + 2πn x₁ = ± (π - π/4) + 2πn x₁= ± 3π/4 + 2πn, n∈Z cosx = √2/2 x₂ = ± arccos(√2/2) + 2πk x₂ = ± π/4 + 2πk, n∈Z