㏒₂²x-3 ㏒₂x-4<0 ОДЗ x>0 . замена ㏒₂x=а
а²-3а-4=0
D=9+16=25
a₁=(3+5)/2=4 ㏒₂x=4 x₁=2⁴=16
a₂=(3-5)/2=-1 ㏒₂x=-1 x₂=2⁻¹=1/2
+ - +
__0____1/2______________16_______________
х∈(1/2 ;16)
㏒₃(5x-1)> ㏒₃(2-3x) ОДЗ 5х-1>0 x>1/5 ; 2-3х>0 x<2/3</strong>
5x-1>2-3x
5x+3x>2+1
8x>3
x>3/8 с учетом ОДЗ
x∈(3/8 ;2/3)